QUOTE(Pukis_miau @ 2015 12 01, 03:40)
Vakar vakare gavau pranešimą į el. paštą, jog atėjo nauja asmeninė žinutė, tačiau paspaudus ant nuorodos vis tiek meta klaidą, o forume nuėjus prie žinučių, man tos žinutės nerodo Taip kad tikrai nėra taip, jog nariai gauna visas žinutes...
QUOTE(***Natalija*** @ 2015 12 01, 03:43)
Ir pas mane taip pat, gaunu pranesima kad ateina zinutes, o iejus i foruma nauju nera. Jau kiek dienu negaliu susirasyti, o taip reikia. LABAI REIKIA
Pas mane irgi tas pats.
Paspaudus ant e-mailo nuorodos apie žinutę, maždaug atsidaro toks tekstas:
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Error Returned
mySQL query error:
SELECT
from_m.member_id AS `id`,
from_m.name,
from_m.mgroup,
from_m.email,
from_m.joined,
from_m.posts,
from_m.last_visit,
from_m.last_activity,
from_m.login_anonymous,
from_m.title,
from_m.hide_email,
from_m.warn_level,
from_m.warn_lastwarn,
g.g_id,
g.g_title,
g.g_icon,
g.g_dohtml,
from_me.msnname,
from_me.aim_name,
from_me.icq_number,
from_me.signature,
from_me.website,
from_me.yahoo,
from_me.location,
from_me.avatar_location,
from_me.avatar_type,
from_me.avatar_size,
mt.*,
mp.*
FROM ibf_message_topic_user_map mtup
JOIN ibf_message_topics mt ON
mt.mt_id = mtup.map_topic_id
JOIN ibf_message_posts mp ON
mp.msg_topic_id = mtup.map_topic_id
JOIN ibf_members from_m ON
from_m.member_id = mp.msg_author_id
JOIN ibf_groups g ON (
g.g_id = from_m.mgroup
)
JOIN ibf_member_extra from_me ON (
from_me.id = from_m.member_id
)
WHERE
mtup.map_user_id = 317035
AND
mp.msg_topic_id = 37620202
AND
mp.msg_id =
mySQL error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 49
mySQL error code:
Date: Tuesday 01st 2015f December 2015 06:46:14 PM
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